最新的C++ Institute CPA - C++ Certified Associate Programmer - CPA-21-02免費考試真題
What is the expected result of the following program?
正確答案: A
Given:
#include <iostream>
#include <exception>
using namespace std;
int main () {
try
{
int * myarray= new int[1000];
}
catch (bad_alloc&)
{
cout << "Error allocating memory";
}
catch (exception& e)
{
cout << "Standard exception";
}
catch (...)
{
cout << "Unknown exception";
}
return 0;
}
What will happen if we use the operator "new" and the memory cannot be allocated?
#include <iostream>
#include <exception>
using namespace std;
int main () {
try
{
int * myarray= new int[1000];
}
catch (bad_alloc&)
{
cout << "Error allocating memory";
}
catch (exception& e)
{
cout << "Standard exception";
}
catch (...)
{
cout << "Unknown exception";
}
return 0;
}
What will happen if we use the operator "new" and the memory cannot be allocated?
正確答案: C
What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
class A {
public :
void print() {
cout << "A ";
}
};
class B {
public :
void print() {
cout << "B ";
}
};
int main() {
B sc[2];
A *bc = (A*)sc;
for (int i=0; i<2;i++)
(bc++)->print();
return 0;
}
#include <iostream>
using namespace std;
class A {
public :
void print() {
cout << "A ";
}
};
class B {
public :
void print() {
cout << "B ";
}
};
int main() {
B sc[2];
A *bc = (A*)sc;
for (int i=0; i<2;i++)
(bc++)->print();
return 0;
}
正確答案: B
What is the output of the program?
#include <iostream>
#include <string>
using namespace std;
union t
{
char c;
int i;
};
class First
{
union t u;
public:
First() {
u.c = 'A';
}
void Print(){
cout << u.c;
}
};
int main()
{
First *t = new First();
t?>Print();
}
#include <iostream>
#include <string>
using namespace std;
union t
{
char c;
int i;
};
class First
{
union t u;
public:
First() {
u.c = 'A';
}
void Print(){
cout << u.c;
}
};
int main()
{
First *t = new First();
t?>Print();
}
正確答案: D
What happens when you attempt to compile and run the following code?
#include <iostream>
#include <string>
using namespace std;
class A {
public:
A() { cout << "A no parameters";}
A(string s) { cout << "A string parameter";}
A(A &a) { cout << "A object A parameter";}
};
class B : public A {
public:
B() { cout << "B no parameters";}
B(string s) { cout << "B string parameter";}
};
int main () {
A a1;
A a2("Test");
B b1("Alan");
return 0;
}
#include <iostream>
#include <string>
using namespace std;
class A {
public:
A() { cout << "A no parameters";}
A(string s) { cout << "A string parameter";}
A(A &a) { cout << "A object A parameter";}
};
class B : public A {
public:
B() { cout << "B no parameters";}
B(string s) { cout << "B string parameter";}
};
int main () {
A a1;
A a2("Test");
B b1("Alan");
return 0;
}
正確答案: C
What is the expected result of the following program?
正確答案: B
What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
int main()
{
int i = 0;
i++;
goto lab;
i++;
lab:
cout<<i;
return 0;
}
#include <iostream>
using namespace std;
int main()
{
int i = 0;
i++;
goto lab;
i++;
lab:
cout<<i;
return 0;
}
正確答案: A
What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
int main (int argc, const char * argv[])
{
int tab[5]={1,2,3};
for (int i=0; i<5; i++)
cout <<tab[i];
return 0;
}
#include <iostream>
using namespace std;
int main (int argc, const char * argv[])
{
int tab[5]={1,2,3};
for (int i=0; i<5; i++)
cout <<tab[i];
return 0;
}
正確答案: D
What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
#define FUN(arg) if(arg) cout<<"Test";
int main()
{
int i=1;
FUN(i<3);
return 0;
}
#include <iostream>
using namespace std;
#define FUN(arg) if(arg) cout<<"Test";
int main()
{
int i=1;
FUN(i<3);
return 0;
}
正確答案: B
Which of the following statements are true? (Choose two.)
正確答案: C,D
What happens when you attempt to compile and run the following code?
#include <iostream>
#include <string>
using namespace std;
class A {
protected:
int y;
public:
int x,z;
A() : x(1), y(2), z(0) { z = x + y; }
A(int a, int b) : x(a), y(b) { z = x + y;}
void Print() { cout << z; }
};
class B : public A {
public:
int y;
B() : A() {}
B(int a, int b) : A(a,b) {}
void Print() { cout << z; }
};
int main () {
A b;
b.Print();
return 0;
}
#include <iostream>
#include <string>
using namespace std;
class A {
protected:
int y;
public:
int x,z;
A() : x(1), y(2), z(0) { z = x + y; }
A(int a, int b) : x(a), y(b) { z = x + y;}
void Print() { cout << z; }
};
class B : public A {
public:
int y;
B() : A() {}
B(int a, int b) : A(a,b) {}
void Print() { cout << z; }
};
int main () {
A b;
b.Print();
return 0;
}
正確答案: D
What is the output of the program?
#include <iostream>
#include <string>
using namespace std;
int main()
{
char str[] = "Hello\0\World\0";
cout << str;
return 0;
}
#include <iostream>
#include <string>
using namespace std;
int main()
{
char str[] = "Hello\0\World\0";
cout << str;
return 0;
}
正確答案: A
What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
class complex{
double re;
double im;
public:
complex() : re(0),im(0) {}
complex(double x) { re=x,im=x;};
complex(double x,double y) { re=x,im=y;}
void print() { cout << re << " " << im;}
};
int main(){
complex c1;
c1 = 3.0;
c1.print();
return 0;
}
#include <iostream>
using namespace std;
class complex{
double re;
double im;
public:
complex() : re(0),im(0) {}
complex(double x) { re=x,im=x;};
complex(double x,double y) { re=x,im=y;}
void print() { cout << re << " " << im;}
};
int main(){
complex c1;
c1 = 3.0;
c1.print();
return 0;
}
正確答案: D
What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
class A
{
public:
virtual void Print(){ cout<<"A";}
};
class B:public A
{
public:
void Print(){ cout<< "B";}
};
int main()
{
A *obj;
A ob1;
obj = &ob1;
obj?>Print();
B ob2;
obj = &ob2;
obj?>Print();
}
#include <iostream>
using namespace std;
class A
{
public:
virtual void Print(){ cout<<"A";}
};
class B:public A
{
public:
void Print(){ cout<< "B";}
};
int main()
{
A *obj;
A ob1;
obj = &ob1;
obj?>Print();
B ob2;
obj = &ob2;
obj?>Print();
}
正確答案: C