最新的Oracle Upgrade to Java SE 7 Programmer - 1Z0-805免費考試真題
Given:
Which design pattern moves the getPerson, createPerson, deletePerson, and updatePerson methods to a new class?
Which design pattern moves the getPerson, createPerson, deletePerson, and updatePerson methods to a new class?
正確答案: D
說明：（僅 Fast2test 成員可見）
Given the code fragment:
private static void copyContents (File source, File target) {
try {inputStream fis = new FileInputStream(source);
outputStream fos = new FileOutputStream (target);
byte [] buf = new byte [8192]; int i;
while ((i = fis.read(buf)) != -1) {
fos.write (buf, 0, i);
}
//insert code fragment here. Line **
System.out.println ("Successfully copied");
}
Which code fragments, when inserted independently at line **, enable the code to compile?
private static void copyContents (File source, File target) {
try {inputStream fis = new FileInputStream(source);
outputStream fos = new FileOutputStream (target);
byte [] buf = new byte [8192]; int i;
while ((i = fis.read(buf)) != -1) {
fos.write (buf, 0, i);
}
//insert code fragment here. Line **
System.out.println ("Successfully copied");
}
Which code fragments, when inserted independently at line **, enable the code to compile?
正確答案: A,C,E
說明：（僅 Fast2test 成員可見）
Given:
private static void copyContents() {
try (
InputStream fis = new FileInputStream("report1.txt");
OutputStream fos = new FileOutputStream("consolidate.txt");
) {
byte[] buf = new byte[8192];
int i;
while ((i = fis.read(buf)) != -1) {
fos.write(buf, 0, i);
}
fis.close();
fis = new FileInputStream("report2.txt");
while ((i = fis.read(buf)) != -1) {
fos.write(buf, 0, i);
}
}
What is the result?
private static void copyContents() {
try (
InputStream fis = new FileInputStream("report1.txt");
OutputStream fos = new FileOutputStream("consolidate.txt");
) {
byte[] buf = new byte[8192];
int i;
while ((i = fis.read(buf)) != -1) {
fos.write(buf, 0, i);
}
fis.close();
fis = new FileInputStream("report2.txt");
while ((i = fis.read(buf)) != -1) {
fos.write(buf, 0, i);
}
}
What is the result?
正確答案: A
說明：（僅 Fast2test 成員可見）
Given the following code fragment:
public static void getInfo() {
//insert code here
List fontCatalog = new ArrayList();
fontCatalog.add("Algerian");
fontCatalog.add("Cambria");
fontCatalog.add("Lucida Bright");
category.put("firstCategory",fontCatalog);
List entrySet = new ArrayList(category.entrySet());
Iterator it = entrySet.iterator();
while(it.hasNext()) {
System.out.println(it.next));
}
}
Which two code fragments, when inserted independently at line **, enable the code to compile?
public static void getInfo() {
//insert code here
List fontCatalog = new ArrayList();
fontCatalog.add("Algerian");
fontCatalog.add("Cambria");
fontCatalog.add("Lucida Bright");
category.put("firstCategory",fontCatalog);
List entrySet = new ArrayList(category.entrySet());
Iterator it = entrySet.iterator();
while(it.hasNext()) {
System.out.println(it.next));
}
}
Which two code fragments, when inserted independently at line **, enable the code to compile?
正確答案: B,D
說明：（僅 Fast2test 成員可見）
Given the code fragment:
Locale loc1 = Locale.getDefault ();
ResourceBundle messages = ResourceBundle.getBundle("MessageBundle", loc1);
Which two statements are a valid way to re-assign a resource bundle to a different Locale?
Locale loc1 = Locale.getDefault ();
ResourceBundle messages = ResourceBundle.getBundle("MessageBundle", loc1);
Which two statements are a valid way to re-assign a resource bundle to a different Locale?
正確答案: A,D
The current working directory is named finance.
Which two code fragments allow you to write the salary.dat file if it does not exist under "finance\payroll"?
Which two code fragments allow you to write the salary.dat file if it does not exist under "finance\payroll"?
正確答案: A,D
說明：（僅 Fast2test 成員可見）
Given the code fragment:
public static void main(String[] args) {
String source = "d:\\company\\info.txt";
String dest = "d:\\company\\emp\\info.txt";
//insert code fragment here Line **
} catch (IOException e) {
System.err.println ("Caught IOException: " + e.getmessage();
}
}
Which two try statements, when inserted at line **, enable the code to successfully move the file info.txt to the destination directory, even if a file by the same name already exists in the destination directory?
public static void main(String[] args) {
String source = "d:\\company\\info.txt";
String dest = "d:\\company\\emp\\info.txt";
//insert code fragment here Line **
} catch (IOException e) {
System.err.println ("Caught IOException: " + e.getmessage();
}
}
Which two try statements, when inserted at line **, enable the code to successfully move the file info.txt to the destination directory, even if a file by the same name already exists in the destination directory?
正確答案: A,D
Given the code fragment:
public static void main(String[] args) {
Path file = Paths.get("D:\\company\\report.txt");
try (SeekableByteChannel sbc = Files.newByteChannel(file,new OpenOption[]
sbc.position(5);
sbc.truncate(30);
} catch (IOException e) {
System.err.printin("Caught IOException: " + e.getMessage () } ;
}
}
What is the result if the report.txt file contains
Welcome to the world of Java?
public static void main(String[] args) {
Path file = Paths.get("D:\\company\\report.txt");
try (SeekableByteChannel sbc = Files.newByteChannel(file,new OpenOption[]
sbc.position(5);
sbc.truncate(30);
} catch (IOException e) {
System.err.printin("Caught IOException: " + e.getMessage () } ;
}
}
What is the result if the report.txt file contains
Welcome to the world of Java?
正確答案: D
說明：（僅 Fast2test 成員可見）
Given the following incorrect program:
class MyTask extends RecursiveTask<Integer> {
final int low;
final int high;
static final int THRESHOLD = /* . . . */
MyTask (int low, int high) { this.low = low; this.high = high; }
Integer computeDirectly()/* . . . */
protected void compute() {
if (high - low <= THRESHOLD)
return computeDirectly();
int mid = (low + high) / 2;
invokeAll(new MyTask(low, mid), new MyTask(mid, high));
Which two changes make the program work correctly?
class MyTask extends RecursiveTask<Integer> {
final int low;
final int high;
static final int THRESHOLD = /* . . . */
MyTask (int low, int high) { this.low = low; this.high = high; }
Integer computeDirectly()/* . . . */
protected void compute() {
if (high - low <= THRESHOLD)
return computeDirectly();
int mid = (low + high) / 2;
invokeAll(new MyTask(low, mid), new MyTask(mid, high));
Which two changes make the program work correctly?
正確答案: D,E
說明：（僅 Fast2test 成員可見）