最新的C++ Institute CPP免費考試真題

問題1

What happens when you attempt to compile and run the following code?
#include <iostream>
#include <algorithm>
#include <vector>
using namespace std;
int main () {
int t[] = {1,2,3,4,5,1,2,3,4,5};
vector<int> v (t,t+10);
vector<int>::iterator it;
int m1[] = {1, 3, 2};
it = find_first_of (v.begin(), v.end(), m1, m1+3);
cout << "First found at position: " << it?v.begin() << endl;
return 0;
}

A. program outputs: First found at position: 1

B. program outputs: First found at position: 0

C. program outputs: First found at position: 6

D. program outputs: First found at position: 10

E. program outputs: First found at position: 5

正確答案: B

問題2

What happens when you attempt to compile and run the following code?
#include <deque>
#include <iostream>
#include <algorithm>
#include <set>
using namespace std;
template<class T>struct Out {
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) { out<<val<<" "; } };
int main() {
int t[]={8, 10, 5, 1, 4, 6, 2, 7, 9, 3};
int t1[]={1,2,3,4};
deque<int> d1(t, t+10);
set<int> s1(t, t+10);
sort(d1.begin(), d1.end());
cout<<includes(s1.begin(),s1.end(), t1,t1+4)<<" "<<includes(d1.begin(),d1.end(), t1,t1+4)
< <endl;
return 0;
}
Program outputs:

A. 0 0

B. 1 1

C. 0 1

D. 1 0

正確答案: B

問題3

What will happen when you attempt to compile and run the code below, assuming that file test.out do not exist before the program execution?
#include <iostream>
# include <fstream>
# include <string>
# include <list>
# include <algorithm>
using namespace std;
template<class T>struct Out {
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) {out<<val<<" "; } };
int main (){
int t[] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
fstream f("test.out");
list<int> l(t, t+10);
for_each(l.begin(), l.end(), Out<int>(f));
f.close();
return 0;
}

A. compilation error

B. no file will be created nor opened

C. file test.out will be created and opened for reading

D. file test.out will be created and opened for writing

E. file test.out will contain sequence 1 2 3 4 5 6 7 8 9 10

正確答案: B

問題4

What happens when you attempt to compile and run the following code?
#include <iostream>
using namespace std;
int main()
{
cout<<100<<" ";
cout.setf(ios::hex);
cout<<100<<" ";
return 0;
}
Program outputs:

A. 100 0x64

B. 100 100

C. 100 64

D. 64 0x64

E. 0x64 0x64

正確答案: B

問題5

What happens when you attempt to compile and run the following code?
# include <iostream>
# include <fstream>
# include <string>
# include <list>
# include <algorithm>
# include <iomanip>
using namespace std;
class B { int val;
public:
B(int v=0):val(v){}
int getV() const {return val;}
operator int() const { return val; };};
template<class T>struct Out {
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) {out<<setw(3)<<hex<<val; } };
int main () {
int t[] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
fstream f("test.out", ios::trunc|ios::out);
list l(t, t+10);
for_each(l.begin(), l.end(), Out(f));
f.close();
f.open("test.out");
for( ; f.good() ; ) {
B i;
f>>i;
cout<<i<<" ";
}
f.close();
return 0;
}

A. program will display sequence 1 2 3 4 5 6 7 8 9 10

B. file test.out will be opened writing

C. compilation error

D. file test.out will be opened for reading

E. file test.out will be truncated

正確答案: C

問題6

What happens when you attempt to compile and run the following code?
# include <iostream>
# include <iomanip>
using namespace std;
int main ()
{
float f = 10.126;
cout<<f<<" "<<setprecision(2)<<f<<endl;
return 0;
}
Program outputs:

A. 10.126 10

B. compilation error

C. 10.126 10.12

D. 10.126 10.13

正確答案: A

問題7

What will happen when you attempt to compile and run the code below, assuming that you enter the following sequence: true true<enter>?
# include <iostream>
# include <string>
using namespace std;
int main ()
{
bool a,b;
cin>>a>>b;
cout<<a<<b<<endl;
return 0;
}
Program will output:

A. truetrue

B. 11

C. none of these

D. 00

E. falsefalse

正確答案: C

問題8

What will happen when you attempt to compile and run the code below, assuming that you enter the following sequence: one two three<enter>?
# include <iostream>
# include <string>
using namespace std;
int main ()
{
string a;
getline(cin, a);
cout<<a<<endl;
return 0;
}
Program will output:

A. runtime exception

B. the result is unspecified

C. compilation error

D. one

E. one two three

正確答案: E

問題9

What happens when you attempt to compile and run the following code?
# include <vector>
# include <iostream>
# include <algorithm>
using namespace std;
template<class T>struct Out {
ostream & out;
Out(ostream & o): out(o){}
void operator()(const T & val ) {
out<<val<<" ";
}
};
struct Sequence {
int start;
Sequence(int start):start(start){}
int operator()() { return 10*(1+(start++ %3)); } };
int main() {
vector<int> v1(10);
vector<int> v2(10);
generate(v1.begin(), v1.end(), Sequence(1));
sort(v1.rbegin(), v1.rend());
unique_copy(v1.begin(),v1.end(), v2.begin());
for_each(v2.begin(), v2.end(), Out<int>(cout) );cout<<endl;
return 0;
}
Program outputs:

A. 30 20 10 0 0 0 0 0 0 0

B. compilation error

C. 30 0 0 0 0 0 0 0 20 10

D. 20 30 10 20 30 10 20 30 10 20

正確答案: A

問題10

What happens when you attempt to compile and run the following code?
#include <iostream>
#include <algorithm>
#include <vector>
#include <set>
using namespace std;
void myfunction(int i) {
cout << " " << i;
}
int multiply (int a) {
return a*2;
}
int main() {
int t[] = { 10, 5, 9, 6, 2, 4, 7, 8, 3, 1 };
vector<int> v1(t, t+10);
set<int> s1(t, t+10);
transform(s1.begin(), s1.end(), v1.begin(), multiply);
transform(v1.begin(), v1.end(), s1.begin(), multiply);
for_each(s1.begin(), s1.end(), myfunction);
return 0;
}
Program outputs:

A. 4 8 12 16 20 24 28 32 36 40

B. compilation error

C. 20 10 18 12 4 8 14 16 6 2

D. 2 4 6 8 10 12 14 16 18 20

正確答案: B

問題11

What happens when you attempt to compile and run the following code?
# include <iostream>
# include <map>
# include <vector>
# include <sstream>
# include <string>
using namespace std;
int main(){
int t[] ={ 3, 4, 2, 1, 6, 5, 7, 9, 8, 0 };
vector<int> v(t, t+10);
map<int,string> m;
for(vector<int>::iterator i=v.begin(); i!=v.end(); i++) {
stringstream s; s<<*i<<*i; m.insert(pair<int,string>(*i,s.str()));
}
for(map<int, string>::iterator i=m.begin();i!= m.end(); i++) {
cout<<*i<<" ";
}
return 0;
}

A. compilation error

B. program outputs: 0 00 1 11 2 22 3 33 4 44 5 55 6 66 7 77 8 88 9 99

C. program outputs: 3 4 2 1 6 5 7 9 8 0

D. program outputs: 00 11 22 33 44 55 66 77 88 99

E. program outputs: 0 1 2 3 4 5 6 7 8 9

正確答案: A

問題12

What happens when you attempt to compile and run the following code?
# include <vector>
# include <iostream>
# include <algorithm>
# include <functional>
using namespace std;
class B { int val;
public:
B(int v=0):val(v){}
int getV() const {return val;}
B operator +(const B &b )const { return B(val + b.val);} };
ostream & operator <<(ostream & out, const B & v) { out<<v.getV(); return out;} template<class T>struct Out {
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) { out<<val<<" "; } };
template<typename A> struct Add : public binary_function<A, A, A> {
A operator() (const A & a, const A & b) const { return a+b; }};
int main() {
int t[]={1,2,3,4,5,6,7,8,9,10};
vector v1(t, t+10);
vector v2(10);
transform(v1.begin(), v1.end(), v2.begin(), bind1st(ptr_fun (Add()), 1)); for_each(v2.rbegin(), v2.rend(), Out(cout));cout<<endl;
return 0;
}
Program outputs:

A. 11 10 9 8 7 6 5 4 3 2

B. 1 2 3 4 5 6 7 8 9 10

C. 2 3 4 5 6 7 8 9 10 11

D. compilation error

E. 10 9 8 7 6 5 4 3 2 1

正確答案: D

問題13

Which pieces of code inserted independently into places marked 1 and 2 will cause the program to compile and display: 0 1 2 3 4 5 6 7 8 9? Choose all that apply.
#include <list>
#include <iostream>
using namespace std;
class A { int a; public:
A(int a){ this?>a=a;}
//insert code here 1
};
//insert code here 2
template<class T> void print(T start, T end) {
while (start != end) {
std::cout << *start << " "; start++;
}
}
int main() {
A t1[] ={ 1, 7, 8, 4, 5 };list<A> l1(t1, t1 + 5);
A t2[] ={ 3, 2, 6, 9, 0 };list<A> l2(t2, t2 + 5);
l1.sort();l2.sort();l1.merge(l2);
print(l1.begin(), l1.end());
print(l2.begin(), l2.end()); cout<<endl;
return 0;
}

A. place 1: bool operator < (const A & b) { return this?>a< b.a;}
place 2: ostream & operator <<(ostream & c, const A & a) { c<<a.a; return c;}

B. place 1: bool operator < (const A & b) { return this?>a< b.a;}
friend ostream & operator <<(ostream & c, const A & a);
place 2: ostream & operator <<(ostream & c, const A & a) { c<<a.a; return c;}

C. place 1: bool operator < (const A & b) { return this?>a< b.a;}

D. place 1: operator int() { return a; }
bool operator < (const A & b) { return this?>a< b.a;}

E. place 1: operator int() { return a; }

正確答案: B,D,E

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